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8k^2-48k-56=0
a = 8; b = -48; c = -56;
Δ = b2-4ac
Δ = -482-4·8·(-56)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-64}{2*8}=\frac{-16}{16} =-1 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+64}{2*8}=\frac{112}{16} =7 $
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